To find the acceleration of a body moving with uniform acceleration, we can use the equation of motion:
v=u+atv = u + atv=u+at
where:
- vvv is the final velocity
- uuu is the initial velocity
- aaa is the acceleration
- ttt is the time taken
In this case, we have two points on the velocity-time graph: (15, 30) and (60, 120). Let's assign the values accordingly:
u=15 m/su = 15 , ext{m/s}u=15m/s and v=120 m/sv = 120 , ext{m/s}v=120m/s
Now, we need to find the time (ttt) it took for the body to change its velocity from uuu to vvv.
Using the equation of motion, we can rearrange it to solve for time:
t=v−uat = frac{{v - u}}{a}t=av−u
Substituting the given values, we have:
t=120 m/s−15 m/sat = frac{{120 , ext{m/s} - 15 , ext{m/s}}}{a}t=a120m/s−15m/s
Now, we can use the other point on the graph, (60, 120), to find the time taken to reach that velocity. Again, using the equation of motion:
t=120 m/s−30 m/sat = frac{{120 , ext{m/s} - 30 , ext{m/s}}}{a}t=<span