To find the instantaneous velocity of the object at t = 2 seconds, we need to take the derivative of the displacement function x(t) with respect to time (t) and then substitute t = 2 seconds into the derivative.
Given: Displacement function: x(t) = 2t + 3t^2
First, let's find the derivative of x(t) with respect to t: v(t) = d/dt (2t + 3t^2) v(t) = 2 + 6t
Now, substitute t = 2 into the velocity function to find the instantaneous velocity at t = 2 seconds: v(2) = 2 + 6(2) v(2) = 2 + 12 v(2) = 14
Therefore, the instantaneous velocity of the object at t = 2 seconds is 14 m/s.