To solve this problem, we need to calculate the distance traveled by the body in the first 5 seconds and the next 5 seconds.
Given: Initial velocity, u = 0 m/s (starting from rest) Final velocity, v = 20 m/s Time, t = 2 seconds (to reach the final velocity)
We can use the equation of motion for uniformly accelerated motion:
v = u + at
where: v = final velocity u = initial velocity a = acceleration t = time
Rearranging the equation, we get:
a = (v - u) / t
Substituting the given values:
a = (20 m/s - 0 m/s) / 2 s a = 10 m/s²
Now, we can calculate the distance traveled in the first 5 seconds. Since the body started from rest, we can use the following equation:
s = ut + (1/2)at²
where: s = distance traveled u = initial velocity t = time a = acceleration
Substituting the values:
s = 0 m/s * 5 s + (1/2)(10 m/s²)(5 s)² s = 0 + (1/2)(10 m/s²)(25 s²) s = (1/2)(10 m/s²)(25 s²) s = 125 m
Therefore, the distance traveled by the body in the first 5 seconds is 125 meters.
For the next 5 seconds, the body continues to move with a constant velocity of 20 m/s. The distance traveled during this time can be calculated using:
s = vt
where: s = distance traveled v = velocity t = time
Substituting the values:
s = 20 m/s * 5 s s = 100 m
Therefore, the distance traveled by the body in the next 5 seconds is 100 meters.