To determine the maximum height attained by an object thrown straight up with an initial velocity of 80 m/s, we can use the equations of motion for vertical motion.
The key equation we'll use is:
v^2 = u^2 + 2as
Where: v = final velocity (which is 0 m/s at the highest point) u = initial velocity (80 m/s) a = acceleration (acceleration due to gravity, which is approximately -9.8 m/s^2) s = displacement (the maximum height we want to find)
Plugging in the values into the equation, we have:
0^2 = (80 m/s)^2 + 2(-9.8 m/s^2)s
Simplifying the equation, we get:
0 = 6400 m^2/s^2 - 19.6 m/s^2s
Rearranging the equation to solve for s:
19.6 m/s^2s = 6400 m^2/s^2 s = 6400 m^2/s^2 / 19.6 m/s^2 s ≈ 326.53 m
Therefore, the maximum height attained by the object is approximately 326.53 meters.