To calculate the atomic mass of dippium, you need to consider the masses and relative abundances of its isotopes. Let's denote the isotope with a relative mass of 17.0 amu as "Dippium-17" and the isotope with a relative mass of 21.3 amu as "Dippium-21.3."
Given that 25.0 percent of dippium atoms are Dippium-17 and 75.0 percent are Dippium-21.3, we can assign their relative abundances as follows:
Relative abundance of Dippium-17 = 0.25 Relative abundance of Dippium-21.3 = 0.75
To calculate the atomic mass, you can use the following formula:
Atomic mass = (Relative abundance of Isotope A * Mass of Isotope A) + (Relative abundance of Isotope B * Mass of Isotope B)
Plugging in the values:
Atomic mass = (0.25 * 17.0 amu) + (0.75 * 21.3 amu) Atomic mass = 4.25 amu + 15.975 amu Atomic mass = 20.225 amu
Therefore, the atomic mass of dippium is approximately 20.225 amu.