To determine which source emits more photons, we need to consider the energy associated with each photon. The energy of a photon can be calculated using Planck's equation:
E = h * f
where E is the energy of the photon, h is Planck's constant (approximately 6.626 x 10^-34 J·s), and f is the frequency of the light.
Now, let's consider the frequency range for red, blue, and yellow light:
Red light: The wavelength of red light is typically around 700-635 nanometers, corresponding to a frequency range of approximately 428-476 THz. Blue light: The wavelength of blue light is typically around 500-450 nanometers, corresponding to a frequency range of approximately 600-670 THz. Yellow light: The wavelength of yellow light is typically around 580-565 nanometers, corresponding to a frequency range of approximately 517-529 THz.
Using the given power of 50 mW (milliwatts), we can calculate the number of photons emitted per second by each source using the following equation:
Number of photons = Power / Energy of each photon
Let's calculate the number of photons emitted per second for each source:
For red light: Frequency (f) = 428-476 THz (converted to Hz) Energy of each photon (E) = h * f
For blue light: Frequency (f) = 600-670 THz (converted to Hz) Energy of each photon (E) = h * f
For yellow light: Frequency (f) = 517-529 THz (converted to Hz) Energy of each photon (E) = h * f
By calculating the number of photons emitted per second for each source, we can determine which source emits more photons.