+9 votes
in Wavelength by
edited by

Your answer

Your name to display (optional):
Privacy: Your email address will only be used for sending these notifications.
+6 votes
by

The energy of a photon can be related to its frequency and wavelength through the following equations:

  1. Energy of a photon (E) = Planck's constant (h) × Frequency (ν)
  2. Speed of light (c) = Frequency (ν) × Wavelength (λ)

Given that the energy of the photon is 30 pJ (picojoules), we can convert it to joules by multiplying by 10^(-12):

E = 30 × 10^(-12) J

Now we can use Equation 1 to find the frequency (ν). Rearranging the equation, we have:

ν = E / h

where Planck's constant (h) is approximately 6.626 × 10^(-34) J·s. Substituting the values, we get:

ν = (30 × 10^(-12) J) / (6.626 × 10^(-34) J·s)

Calculating the result:

ν ≈ 4.529 × 10^21 Hz

To find the wavelength (λ), we can use Equation 2. Rearranging the equation, we have:

λ = c / ν

where the speed of light (c) is approximately 3.0 × 10^8 m/s. Substituting the values, we get:

λ = (3.0 × 10^8 m/s) / (4.529 × 10^21 Hz)

Calculating the result:

λ ≈ 6.62 × 10^(-14) meters or 66.2 femtometers (fm)

Therefore, the frequency of the photon is approximately 4.529 × 10^21 Hz, and the wavelength is approximately 6.62 × 10^(-14) meters (66.2 femtometers).

Welcome to Physicsgurus Q&A, where you can ask questions and receive answers from other members of the community.
...