In the given wave equation, y = (2.00 cm) sin(kx - wt), we can determine the amplitude, wavelength, frequency, and speed of the wave using the following relationships:
Amplitude (A): The amplitude of the wave is the maximum displacement of a particle from its equilibrium position. In this case, the amplitude is given as 2.00 cm.
Wavelength (λ): The wavelength is the distance between two consecutive points in phase. It can be determined using the formula: λ = 2π/k, where k is the wave number. In this case, k = 2.11 rad/m. Therefore:
λ = 2π/2.11 rad/m ≈ 2.99 m
Frequency (f): The frequency of the wave is the number of complete oscillations or cycles per unit time. It can be calculated using the formula: f = w/2π, where w is the angular frequency. In this case, w = 3.62 rad/s. Therefore:
f = 3.62 rad/s / (2π) ≈ 0.576 Hz
Speed (v): The speed of a wave is given by the product of the frequency and the wavelength. In this case:
v = λf ≈ 2.99 m × 0.576 Hz ≈ 1.72 m/s
So, the amplitude of the wave is 2.00 cm, the wavelength is approximately 2.99 m, the frequency is approximately 0.576 Hz, and the speed of the wave is approximately 1.72 m/s.