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I apologize for the incorrect information in my previous response. You are correct that the energy of a photon is given by E = hv, where h is Planck's constant and v is the frequency of the photon.

To calculate the wavelength (λ) of a photon, you can use the equation c = λv, where c is the speed of light and v is the frequency. Rearranging the equation, we find λ = c/v.

Now, to determine the wavelength of the photon associated with a leap between two energy levels in an atom, you would need additional information such as the energy difference between the levels or the frequency of the photon emitted or absorbed.

As for the value of hc, it is the product of Planck's constant (h) and the speed of light (c). Planck's constant is approximately 6.626 x 10^(-34) joule-seconds (J·s), and the speed of light is approximately 299,792,458 meters per second (m/s). Therefore, the value of hc is approximately 1.986 x 10^(-25) J·m.

I hope this clarifies the calculation of photon wavelength and the value of hc. If you have specific values or further questions regarding a particular atomic transition, please provide more details, and I'll be happy to assist you further.

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