To determine the energy of a photon, you can use the equation:
E = (hc) / λ
Where: E is the energy of the photon, h is Planck's constant (approximately 6.626 x 10^-34 joule-seconds), c is the speed of light in a vacuum (approximately 3.00 x 10^8 meters per second), λ is the wavelength of the photon.
Given a wavelength of 6000 units (you haven't specified the units, so I'll assume it's in angstroms, which is a common unit for expressing light wavelengths), we first need to convert it to meters:
λ = 6000 angstroms = 6000 x 10^-10 meters
Now, we can calculate the energy of the photon:
E = (6.626 x 10^-34 J·s * 3.00 x 10^8 m/s) / (6000 x 10^-10 m) E ≈ 3.31 x 10^-19 joules
Therefore, the energy of a photon with a wavelength of 6000 angstroms is approximately 3.31 x 10^-19 joules.