To calculate the energy of a single quantum of X-ray with a given wavelength, you can use the formula:
Energy (E) = (Planck's constant, h) × (speed of light, c) / (wavelength, λ)
The value of Planck's constant (h) is approximately 6.626 × 10^-34 joule-seconds, and the speed of light (c) is approximately 3.0 × 10^8 meters per second.
Let's calculate the energy using the given wavelength of 2.36 nm (which can be converted to meters by multiplying by 10^-9):
λ = 2.36 nm = 2.36 × 10^-9 m
Now, we can plug these values into the formula:
E = (6.626 × 10^-34 J·s) × (3.0 × 10^8 m/s) / (2.36 × 10^-9 m)
Simplifying the expression:
E = 7.99 × 10^-16 J
Therefore, the energy of one quantum of X-ray with a wavelength of 2.36 nm is approximately 7.99 × 10^-16 joules.