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To determine what happens to the wavelength of a wave when its speed is quadrupled while the frequency is doubled, we can use the equation that relates the speed, frequency, and wavelength of a wave.

The equation is:

v = λf

where v represents the speed of the wave, λ represents the wavelength, and f represents the frequency.

Let's consider the initial values:

Speed (v₁) = Initial speed Frequency (f₁) = Initial frequency Wavelength (λ₁) = Initial wavelength

And the final values after the changes:

Speed (v₂) = Quadrupled speed (4 times the initial speed) Frequency (f₂) = Doubled frequency (2 times the initial frequency) Wavelength (λ₂) = Unknown (what we're trying to determine)

Using the equation, we have:

v₁ = λ₁f₁ (Initial equation) v₂ = λ₂f₂ (Final equation)

Since the frequency is doubled (f₂ = 2f₁) and the speed is quadrupled (v₂ = 4v₁), we can rewrite the final equation as:

4v₁ = λ₂(2f₁)

Dividing both sides of the equation by 2f₁:

2v₁ / f₁ = λ₂

Now, let's substitute the expression for speed (v) in terms of wavelength (λ) and frequency (f) from the initial equation:

2(λ₁f₁) / f₁ = λ₂

Simplifying:

2λ₁ = λ₂

Therefore, when the speed is quadrupled while the frequency is doubled, the wavelength remains unchanged. The wavelength of the wave remains the same in this scenario.

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