To find the new wavelength of green light when it travels through water, we can use Snell's law, which relates the incident angle and the refractive indices of the two mediums involved. The formula is:
n1 * sin(theta1) = n2 * sin(theta2)
where: n1 = refractive index of the first medium (initial medium, in this case, vacuum) theta1 = angle of incidence (which is usually 0 degrees for normal incidence) n2 = refractive index of the second medium (final medium, in this case, water) theta2 = angle of refraction
Since the angle of incidence is 0 degrees for normal incidence, sin(theta1) is 0, and the equation simplifies to:
0 = n2 * sin(theta2)
In this case, we're given the refractive index of water (n2 = 1.33). Let's assume the new wavelength of green light in water is λw.
Using the equation:
n1 * lambda1 = n2 * lambda2
where: n1 = refractive index of the first medium (initial medium, vacuum) lambda1 = wavelength of light in the first medium (vacuum) n2 = refractive index of the second medium (water) lambda2 = wavelength of light in the second medium (water)
Substituting the given values:
1 * (504 * 10^(-9)) = 1.33 * lambda2
Solving for lambda2:
lambda2 = (504 * 10^(-9)) / 1.33 ≈ 378.95 * 10^(-9) m
Therefore, the new wavelength of green light when it travels through water is approximately 378.95 * 10^(-9) meters.