The wavelength of a note emitted by a closed organ pipe can be calculated using the formula:
λ = 4L/n
where λ is the wavelength, L is the length of the pipe, and n is the harmonic number.
In the case of a closed organ pipe, the fundamental frequency (first harmonic) is produced when n = 1. Therefore, for the fundamental frequency, the formula becomes:
λ = 4L
Given that the length of the closed organ pipe is 32.4 cm (0.324 meters), we can calculate the wavelength as follows:
λ = 4 * 0.324
λ ≈ 1.296 meters
So, the wavelength of the note emitted by a closed organ pipe 32.4 cm long at 0°C is approximately 1.296 meters.