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To determine the velocity of the particle when t = 2s, we can use the equation of motion for constant acceleration:

v = u + at

Where: v = final velocity u = initial velocity a = acceleration t = time

In this case, the given acceleration is a = -0.2 m/s (negative because it is in the opposite direction to the initial velocity), and the initial velocity is u = 80 m/s. We want to find the velocity when t = 2s. Plugging in the values into the equation, we get:

v = 80 m/s + (-0.2 m/s) * 2 s

Simplifying the equation:

v = 80 m/s - 0.4 m/s v = 79.6 m/s

Therefore, when t = 2s, the velocity of the particle is 79.6 m/s.

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