To determine the velocity of the particle when t = 2s, we can use the equation of motion for constant acceleration:
v = u + at
Where: v = final velocity u = initial velocity a = acceleration t = time
In this case, the given acceleration is a = -0.2 m/s (negative because it is in the opposite direction to the initial velocity), and the initial velocity is u = 80 m/s. We want to find the velocity when t = 2s. Plugging in the values into the equation, we get:
v = 80 m/s + (-0.2 m/s) * 2 s
Simplifying the equation:
v = 80 m/s - 0.4 m/s v = 79.6 m/s
Therefore, when t = 2s, the velocity of the particle is 79.6 m/s.