Question

A ball is thrown with a velocity of 20m/s at an angle of 45 degrees above the horizontal. What is the ball’s velocity?

Answer 1

To determine the velocity of the ball, we need to break it down into its horizontal and vertical components. Given the initial velocity of 20 m/s at an angle of 45 degrees above the horizontal, we can calculate the horizontal and vertical components of the velocity.

The horizontal component of the velocity ($v_x$) can be determined using the formula:

$v_x=v\cdot \cos (\theta )$

where $v$ is the initial velocity (20 m/s) and $\theta$ is the angle (45 degrees).

Plugging in the values:

$v_x=20\text{m/s}\cdot \cos (45^{\circ })$

Using the value of $\cos (45^{\circ })=\frac{\sqrt{2}}{2}$:

$v_x=20\text{m/s}$