Question

A ball is thrown upward with an initial velocity of 29 m/s. The approximate value of g is 10m/s^2. At what time does the ball reach the high point in its flight?

Answer 1

To determine the time it takes for the ball to reach the highest point in its flight, we can use the kinematic equation for vertical motion:

$v_f=v_i+at$

Where:

• $v_f$ is the final velocity (0 m/s at the highest point, as the ball momentarily stops before descending).
• $v_i$ is the initial velocity (29 m/s in the upward direction).
• $a$ is the acceleration due to gravity (-10 m/s² since it acts downward).
• $t$ is the time.

Since the final velocity is 0 m/s, we can rearrange the equation to solve for $t$:

$0=29-10t$

Simplifying further:

$10t=29$

Dividing both sides by 10:

$t=\frac{29}{10}=2.9\text{ seconds}$

Therefore, it takes approximately 2.9 seconds for the ball to reach the highest point in its flight.