To find the distance the car travels while accelerating, we can use the kinematic equation:
d=vit+12at2d = v_i t + frac{1}{2} a t^2d=vit+21at2
where: ddd is the distance traveled, viv_ivi is the initial velocity, aaa is the acceleration, and ttt is the time.
Given: vi=20 m/sv_i = 20 , ext{m/s}vi=20m/s, a=3 m/s2a = 3 , ext{m/s}^2a=3m/s2, and t=5 st = 5 , ext{s}t=5s.
Substituting these values into the equation, we have:
d=(20 m/s)(5 s)+12(3 m/s2)(5 s)2d = (20 , ext{m/s})(5 , ext{s}) + frac{1}{2}(3 , ext{m/s}^2)(5 , ext{s})^2d=(20m/s)(5s)+21</span