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To find the distance the car travels while accelerating, we can use the kinematic equation:

d=vit+12at2d = v_i t + frac{1}{2} a t^2

where: dd is the distance traveled, viv_i is the initial velocity, aa is the acceleration, and tt is the time.

Given: vi=20 m/sv_i = 20 , ext{m/s}, a=3 m/s2a = 3 , ext{m/s}^2, and t=5 st = 5 , ext{s}.

Substituting these values into the equation, we have:

d=(20 m/s)(5 s)+12(3 m/s2)(5 s)2d = (20 , ext{m/s})(5 , ext{s}) + frac{1}{2}(3 , ext{m/s}^2)(5 , ext{s})^2

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