Question

A body starts from rest and moves with uniform acceleration of 6m/s^2. What distance does it cover in the third second?

Answer 1

To find the distance covered by a body starting from rest and moving with uniform acceleration, we can use the following kinematic equation:

$d=ut+\frac{1}{2}a{t}^2$

Where:

• d is the distance covered
• u is the initial velocity (0 m/s since it starts from rest)
• a is the acceleration (6 m/s²)
• t is the time (3 seconds)

Plugging in the given values into the equation, we can calculate the distance covered in the third second:

$d=0\cdot 3+\frac{1}{2}\cdot 6\cdot (3^2)$

Simplifying the equation:

$d=0+\frac{1}{2}\cdot 6\cdot 9$

$d=\frac{1}{2}\cdot 54$

$d=27$

Therefore, the distance covered in the third second is 27 meters.