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To find the horizontal distance traveled by the ball after 1 second, we can calculate the horizontal component of the velocity and then multiply it by the time.

Given: Initial velocity (u) = 30 m/s Launch angle (θ) = 45° Time (t) = 1 second Acceleration due to gravity (g) = 10 m/s²

First, let's find the horizontal component of the initial velocity (u_x):

u_x = u * cos(θ)

Substituting the values into the formula:

u_x = 30 m/s * cos(45°) = 30 m/s * √2 / 2 = 15√2 m/s

Now, we can calculate the horizontal distance (x) traveled by the ball after 1 second using the formula:

x = u_x * t

Substituting the values into the formula:

x = 15√2 m/s * 1 s ≈ 15√2 m/s

Therefore, the distance of the ball from its point of projection after 1 second is approximately 15√2 meters.

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