To find the horizontal distance traveled by the ball after 1 second, we can calculate the horizontal component of the velocity and then multiply it by the time.
Given: Initial velocity (u) = 30 m/s Launch angle (θ) = 45° Time (t) = 1 second Acceleration due to gravity (g) = 10 m/s²
First, let's find the horizontal component of the initial velocity (u_x):
u_x = u * cos(θ)
Substituting the values into the formula:
u_x = 30 m/s * cos(45°) = 30 m/s * √2 / 2 = 15√2 m/s
Now, we can calculate the horizontal distance (x) traveled by the ball after 1 second using the formula:
x = u_x * t
Substituting the values into the formula:
x = 15√2 m/s * 1 s ≈ 15√2 m/s
Therefore, the distance of the ball from its point of projection after 1 second is approximately 15√2 meters.